(xy)dx=(1+x^2)dy

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Solution for (xy)dx=(1+x^2)dy equation:


Simplifying
(xy) * dx = (1 + x2) * dy

Multiply xy * dx
dx2y = (1 + x2) * dy

Reorder the terms for easier multiplication:
dx2y = dy(1 + x2)
dx2y = (1 * dy + x2 * dy)

Reorder the terms:
dx2y = (dx2y + 1dy)
dx2y = (dx2y + 1dy)

Add '-1dx2y' to each side of the equation.
dx2y + -1dx2y = dx2y + -1dx2y + 1dy

Combine like terms: dx2y + -1dx2y = 0
0 = dx2y + -1dx2y + 1dy

Combine like terms: dx2y + -1dx2y = 0
0 = 0 + 1dy
0 = 1dy

Solving
0 = 1dy

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1dy' to each side of the equation.
0 + -1dy = 1dy + -1dy
Remove the zero:
-1dy = 1dy + -1dy

Combine like terms: 1dy + -1dy = 0
-1dy = 0

Divide each side by '-1'.
dy = 0

Simplifying
dy = 0

The solution to this equation could not be determined.

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